Olimpiade

Geometry Problem Series#2

Capture

In triangle ABC, D is the midpoint of BC and E is the midpoint of CA. AD and

BE are perpendicular to each other. The diagram below shows the point G where they intersect. This point is called the centroid of ABC, and has the property that AG = 2DG and BG = 2EG. What is the value of \( \frac{BC^2+AB^2}{AB^2}\) ?

Ilustrasi problem 2

Sumber Soal

Sumber soal problem 2

Solusi, klik link berikut ini.

Leave a Reply

Your email address will not be published. Required fields are marked *